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CGP EDU Academic Team
Published on: August 14, 2026
The solution of the differential equation y (2x 4 + y)dy + (4xy 2 -1)x 2 dx = 0 is (where C is an arbitrary constant)
Text Solution
Verified by ExpertsThe correct answer is:
B
3x 4 y 2 + y 3 - x 3 = C
2x 4 ydy + y 2 dy + 4x 3 y 2 dx - x 2 dx = 0
2x 3 y (xdy + 2ydx) + y 2 dy - x 2 dx = 0
2x 2 y (x 2 dy + 2xydx) + y 2 dy - x 2 dx = 0
2 (x 2 y)d (x 2 y) + y 2 dy - x 2 dx = 0
On integrating, we get,
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